37
=
3x2x1 / 1
=
6 / 1
=
6 (AB, AC, BA, BC, CA, CB)
ii.
C
=
3! / 2! (3-2)!
=
3x2x1 / 2x1 (1)
=
6 / 2
=
3 (AB, AC, BC; AB dan BA dianggap sama)
 |
|
37
=
3x2x1 / 1
=
6 / 1
=
6 (AB, AC, BA, BC, CA, CB)
ii.
C
=
3! / 2! (3-2)!
=
3x2x1 / 2x1 (1)
=
6 / 2
=
3 (AB, AC, BC; AB dan BA dianggap sama)
|