106
?©
= 363
c
= 3,63
2
k
/
s
(
N
?
x
2
)
-
(
?
x
)
2
2
16,5
(100.1755)
(131769)
363
i
?
x
i
N’ =
=
=
90,35
i
N’ =N, maka jumlah data cukup.
Tabel 5.17 Pengumpulan Data Sobek Polos
No.
Nonconformities
No.
Nonconformities
No.
Nonconformities
No.
Nonconformities
1
4
26
5
51
2
76
7
2
2
27
2
52
7
77
4
3
5
28
4
53
2
78
3
4
4
29
2
54
6
79
2
5
2
30
8
55
7
80
5
6
4
31
1
56
2
81
2
7
6
32
4
57
3
82
8
8
6
33
2
58
5
83
1
9
3
34
4
59
2
84
2
10
8
35
3
60
3
85
3
11
2
36
3
61
4
86
2
12
3
37
2
62
4
87
4
13
5
38
11
63
2
88
5
14
3
39
5
64
3
89
2
15
2
40
2
65
3
90
2
16
7
41
4
66
3
91
10
17
2
42
0
67
2
92
4
18
7
43
4
68
4
93
2
19
2
44
2
69
5
94
0
20
2
45
4
70
5
95
3
21
4
46
3
71
4
96
2
22
8
47
2
72
3
97
4
23
3
48
4
73
2
98
3
24
5
49
2
74
4
99
2
25
2
50
4
75
2
100
2
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