107
?©
= 361
c
= 3,61
2
k
/
s
(
N
?
x
2
)
-
(
?
x
)
2
2
16,5
(100.1707)
(130321)
361
i
?
x
i
N’ =
=
=
84,35
i
N’ =N, maka jumlah data cukup.
Tabel 5.18 Pengumpulan Data Patah Jarum Polos
No.
Nonconformities
No.
Nonconformities
No.
Nonconformities
No.
Nonconformities
1
2
26
1
51
4
76
5
2
4
27
1
52
2
77
4
3
5
28
7
53
4
78
2
4
2
29
4
54
2
79
3
5
6
30
2
55
2
80
4
6
2
31
2
56
5
81
3
7
4
32
7
57
3
82
3
8
10
33
3
58
7
83
2
9
2
34
2
59
4
84
4
10
5
35
2
60
2
85
2
11
3
36
6
61
2
86
2
12
4
37
7
62
4
87
1
13
2
38
2
63
2
88
2
14
4
39
2
64
5
89
3
15
3
40
2
65
2
90
0
16
7
41
10
66
6
91
3
17
5
42
3
67
4
92
5
18
5
43
0
68
5
93
6
19
2
44
1
69
2
94
5
20
4
45
4
70
3
95
4
21
1
46
6
71
6
96
2
22
2
47
2
72
3
97
4
23
2
48
2
73
4
98
6
24
3
49
5
74
4
99
5
25
2
50
3
75
2
100
2
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